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Using a table format to run a list,
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Updated: 9 Feb 2003 |
This example has eleven fighters in a double-elimination list.
Having an odd number of fighters is no problem when using a table format.
ROUND ONE
Line up the bouts as in Example 1. Instead of a bye fight, #11 will fight in the first bout of the next round. For this example, it will be against the winner of the first bout in this round. (In the next example, we'll use the loser of the first bout instead.)
The randomized results: Fighters #1, #2, #3, #9, and #10 win their bouts.
Ftr Round
1
1 6/W
2 7/W
3 8/W
4 9/L
5 10/L
6 1/L
7 2/L
8 3/L
9 4/W
10 5/W
11 ---
ROUND TWO
To plan the bouts for this round, put #11 first then (like we did in Example 1) list the bouts from the previous round with the winners first, like so: [#11], #1-#6, #2-#7, #3-#8, #9-#4, #10-#5.
Alternate the "winner" bouts with the "loser" bouts based only on the results of the previous round.
#11 vs #1, #6 vs #7, #2 vs #3, #8 vs #4, #9 vs #10 and we sit out #5.
In the first bout of the next round, #5 will face the winner of the first bout of this round – unless we come up with something better...
The results: #1, #6, #3, #4, and #10 win.
Ftr Round Round
1 2
1 6/W 11/W
2 7/W 3/L
3 8/W 2/W
4 9/L 8/W
5 10/L ---
6 1/L 7/W
7 2/L 6/L
8 3/L 4/L
9 4/W 10/L
10 5/W 9/W
11 --- 1/L
Out of the list with two losses: Fighters #7, #8.
ROUND THREE
Listing #5 first, the bouts from the previous round, with winners first AND dropping the fighters who are now out, were: [#5], #1-#11, #6, #3-#2, #4, #10-#9
The first bout for this round: #5 vs #11. Why? It makes more sense than #5-#1, because #5 and #11 have both sat out already and both have the same record of 0-1.
Then, #1 vs #6 ? ... Nope, they fought in Round 1. Now we start adjusting.
#5 vs #11, #1 vs #3, #6 vs #4, #2 vs #9, and we sit out #10.
The results: #5, #3, #6, and #2 win.
Ftr Round Round Round
1 2 3
1 6/W 11/W 3/L
2 7/W 3/L 9/W
3 8/W 2/W 1/W
4 9/L 8/W 6/L
5 10/L --- 11/W
6 1/L 7/W 4/W
7 2/L 6/L out
8 3/L 4/L out
9 4/W 10/L 2/L
10 5/W 9/W ---
11 --- 1/L 5/L
Out with two losses: #4, #9, #11.
ROUND FOUR
The bouts from the previous round, with #10 first: [#10], #5, #3-#1, #6, #2.
#10 and #5 faced each other in Round 1, so we put #10 vs #3.
#1 and #5 both have a loss, so that's a good match.
#2 and #6 haven't faced each other, so we're good to go!
The results: #10, #1, and #6 win.
Ftr Round Round Round Round
1 2 3 4
1 6/W 11/W 3/L 5/W
2 7/W 3/L 9/W 6/L
3 8/W 2/W 1/W 10/L
4 9/L 8/W 6/L out
5 10/L --- 11/W 1/L
6 1/L 7/W 4/W 2/W
7 2/L 6/L out
8 3/L 4/L out
9 4/W 10/L 2/L out
10 5/W 9/W --- 3/W
11 --- 1/L 5/L out
Out with two losses: #2, #5.
ROUND FIVE
The bouts from the previous round were: #10-#3, #1, #6.
Easy choice, isn't it? #10 vs #1, #3 vs #6.
The results: #10 and #6 win.
Ftr Round Round Round Round Round
1 2 3 4 5
1 6/W 11/W 3/L 5/W 10/L
2 7/W 3/L 9/W 6/L out
3 8/W 2/W 1/W 10/L 6/L
4 9/L 8/W 6/L out
5 10/L --- 11/W 1/L out
6 1/L 7/W 4/W 2/W 3/W
7 2/L 6/L out
8 3/L 4/L out
9 4/W 10/L 2/L out
10 5/W 9/W --- 3/W 1/W
11 --- 1/L 5/L out
Out with two losses: #1, #3.
ROUND SIX
This is the final round – with #6 vs #10.
#6 is 4-1 and #10 is 4-0 ... assigning an extra fight for #10 is an option that could be offered to #6.
If so, Fighters #1 and #3 are obvious choices. #10 has fought both of them in the tourney recently, so whichever was a better match (Round Four vs #3 or Round Five vs #1) should be the first choice for the bye fight. If both #3 and #1 are tired, just work down the list of finishers, #2 or #5 would be next; note that #10 didn't fight #2 in this list.
When #6 and #10 do meet, the finals could be a "true" best two out of three as covered in Example 1, or the difference could be ignored. Whatever works.
Table format: Introduction • Example 1 • Example 3
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Original page posted: July 7, 2001 • Last tweaked:
May 14, 2009
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